Part A
A small metal particle passes downward through a fluid medium while being subjected to the attraction of a magnetic field such that its position is observed to be s=(15t3−3t) mm, where t is measured in seconds. Determine (a) the particle's displacement from t=2 s to t=4 s, and (b) the velocity and acceleration of the particle when t=5 s.
s(2)=114 mm
s(4)=948 mm
displacement = s(4)-s(2) = 834 mm
v=ds/dt
v=45t2-3
a=dv/dt
a=90t
v(5)=1122 mm/s
a(5)=450 mm/s2
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