adsense

Thursday, September 17, 2015

Uniform Circular Motion
Learning Goal:
To find the velocity and acceleration of an object undergoing uniform circular motion.
Suppose that a particle's position is given by the following expression:
r(t)=R[cos(ωt)i+sin(ωt)j]
 =Rcos(ωt)i+Rsin(ωt)j
where ω is the constant value of the particle's angular velocity.

Motion of the particle
Time required by the particle to cross the negative x axis for the first time
When does the particle first cross the negative x axis?

Velocity of the particle
Find the particle's velocity as a function of time, v(t) .
Speed of the particle
Find the particle’s speed at time t .



Acceleration of the particle as a function of time
Find the particle’s acceleration as a function of time.
a(t)=R[-w^2cos(wt)i--w^2sin(wt)j]

Acceleration of the particle in terms of position
Your calculation is actually a derivation of the centripetal acceleration. To see this, express the particle’s acceleration in terms of its position, r(t) .
Magnitude of the particle's acceleration
Find the acceleration vector’s magnitude as a function of time.


Magnitude of the particle's acceleration in terms of the radius of rotation and the particle’s linear speed
Express the magnitude of the particle's acceleration vector in terms of R and v using the expression you obtained for the particle’s speed (from Part D).

No comments:

Post a Comment